Base | Representation |
---|---|
bin | 100011111101110001111101… |
… | …0010110000001101000110111 |
3 | 1112111010011202212210212111222 |
4 | 1013323203322112001220313 |
5 | 312431122112133411210 |
6 | 3040455055251420555 |
7 | 123430562513340515 |
oct | 10773437226015067 |
9 | 1474104685725458 |
10 | 316354311232055 |
11 | 91889123394738 |
12 | 2b5937028b475b |
13 | 1076a111711515 |
14 | 58198b79d54b5 |
15 | 268917cee0655 |
hex | 11fb8fa581a37 |
316354311232055 has 16 divisors (see below), whose sum is σ = 382736411668800. Its totient is φ = 251017314020352.
The previous prime is 316354311232019. The next prime is 316354311232079. The reversal of 316354311232055 is 550232113453613.
It is a cyclic number.
It is not a de Polignac number, because 316354311232055 - 218 = 316354310969911 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 316354311231997 and 316354311232015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 501173594 + ... + 501804423.
It is an arithmetic number, because the mean of its divisors is an integer number (23921025729300).
Almost surely, 2316354311232055 is an apocalyptic number.
316354311232055 is a deficient number, since it is larger than the sum of its proper divisors (66382100436745).
316354311232055 is a wasteful number, since it uses less digits than its factorization.
316354311232055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1002978538.
The product of its (nonzero) digits is 972000, while the sum is 44.
Adding to 316354311232055 its reverse (550232113453613), we get a palindrome (866586424685668).
The spelling of 316354311232055 in words is "three hundred sixteen trillion, three hundred fifty-four billion, three hundred eleven million, two hundred thirty-two thousand, fifty-five".
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