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31640004613 = 74520000659
BaseRepresentation
bin11101011101111001…
…000010100000000101
310000200001020202202201
4131131321002200011
51004244320121423
622311335034501
72200032413260
oct353571024005
9100601222681
1031640004613
1112466a59848
12617020ba31
132ca3096829
141762193cd7
15c52acb2ad
hex75de42805

31640004613 has 4 divisors (see below), whose sum is σ = 36160005280. Its totient is φ = 27120003948.

The previous prime is 31640004587. The next prime is 31640004637.

31640004613 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31640004613 - 225 = 31606450181 is a prime.

It is a super-2 number, since 2×316400046132 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31640004013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2260000323 + ... + 2260000336.

It is an arithmetic number, because the mean of its divisors is an integer number (9040001320).

Almost surely, 231640004613 is an apocalyptic number.

It is an amenable number.

31640004613 is a deficient number, since it is larger than the sum of its proper divisors (4520000667).

31640004613 is an equidigital number, since it uses as much as digits as its factorization.

31640004613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4520000666.

The product of its (nonzero) digits is 5184, while the sum is 28.

It can be divided in two parts, 3164000 and 4613, that added together give a palindrome (3168613).

The spelling of 31640004613 in words is "thirty-one billion, six hundred forty million, four thousand, six hundred thirteen".

Divisors: 1 7 4520000659 31640004613