Base | Representation |
---|---|
bin | 100011111111111011101101… |
… | …0101100110010111011111001 |
3 | 1112112011110100012210110102202 |
4 | 1013333313122230302323321 |
5 | 313000443433031324112 |
6 | 3041243021332235545 |
7 | 123461134325451305 |
oct | 10777673254627371 |
9 | 1475143305713382 |
10 | 316650133073657 |
11 | 91992627082769 |
12 | 2b620b00a6bbb5 |
13 | 1078bc96a40b46 |
14 | 5829d3bc88d05 |
15 | 2691be39866c2 |
hex | 11ffddab32ef9 |
316650133073657 has 4 divisors (see below), whose sum is σ = 330417530163840. Its totient is φ = 302882735983476.
The previous prime is 316650133073647. The next prime is 316650133073777. The reversal of 316650133073657 is 756370331056613.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 316650133073657 - 242 = 312252086562553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (316650133073647) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6883698545057 + ... + 6883698545102.
It is an arithmetic number, because the mean of its divisors is an integer number (82604382540960).
Almost surely, 2316650133073657 is an apocalyptic number.
It is an amenable number.
316650133073657 is a deficient number, since it is larger than the sum of its proper divisors (13767397090183).
316650133073657 is a wasteful number, since it uses less digits than its factorization.
316650133073657 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13767397090182.
The product of its (nonzero) digits is 21432600, while the sum is 56.
The spelling of 316650133073657 in words is "three hundred sixteen trillion, six hundred fifty billion, one hundred thirty-three million, seventy-three thousand, six hundred fifty-seven".
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