Base | Representation |
---|---|
bin | 1001001101111011100… |
… | …01110011001011101011 |
3 | 1010021111112002022121212 |
4 | 10212331301303023223 |
5 | 20142113414424011 |
6 | 401255251023335 |
7 | 31611350231225 |
oct | 4467561631353 |
9 | 1107445068555 |
10 | 316716561131 |
11 | 112356273083 |
12 | 5146b89ab4b |
13 | 23b351a22b9 |
14 | 1148731d415 |
15 | 838a04908b |
hex | 49bdc732eb |
316716561131 has 2 divisors, whose sum is σ = 316716561132. Its totient is φ = 316716561130.
The previous prime is 316716561071. The next prime is 316716561157. The reversal of 316716561131 is 131165617613.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 316716561131 - 222 = 316712366827 is a prime.
It is a super-2 number, since 2×3167165611312 (a number of 24 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (316716561631) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158358280565 + 158358280566.
It is an arithmetic number, because the mean of its divisors is an integer number (158358280566).
Almost surely, 2316716561131 is an apocalyptic number.
316716561131 is a deficient number, since it is larger than the sum of its proper divisors (1).
316716561131 is an equidigital number, since it uses as much as digits as its factorization.
316716561131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 68040, while the sum is 41.
The spelling of 316716561131 in words is "three hundred sixteen billion, seven hundred sixteen million, five hundred sixty-one thousand, one hundred thirty-one".
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