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3171105581057 is a prime number
BaseRepresentation
bin101110001001010100100…
…111110010100000000001
3102020011011210121101122222
4232021110213302200001
5403423411012043212
610424441421540425
7445050644461451
oct56112447624001
912204153541588
103171105581057
1110129494802a7
124326b8a14715
131a005984005b
14ad6a7721d61
155774b178c72
hex2e2549f2801

3171105581057 has 2 divisors, whose sum is σ = 3171105581058. Its totient is φ = 3171105581056.

The previous prime is 3171105581009. The next prime is 3171105581129. The reversal of 3171105581057 is 7501855011713.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2961964913296 + 209140667761 = 1721036^2 + 457319^2 .

It is an emirp because it is prime and its reverse (7501855011713) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3171105581057 - 214 = 3171105564673 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3171105580999 and 3171105581017.

It is not a weakly prime, because it can be changed into another prime (6171105581057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1585552790528 + 1585552790529.

It is an arithmetic number, because the mean of its divisors is an integer number (1585552790529).

Almost surely, 23171105581057 is an apocalyptic number.

It is an amenable number.

3171105581057 is a deficient number, since it is larger than the sum of its proper divisors (1).

3171105581057 is an equidigital number, since it uses as much as digits as its factorization.

3171105581057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 147000, while the sum is 44.

The spelling of 3171105581057 in words is "three trillion, one hundred seventy-one billion, one hundred five million, five hundred eighty-one thousand, fifty-seven".