Base | Representation |
---|---|
bin | 101110001100000011001… |
… | …011011110100011010101 |
3 | 102020102201220021020100112 |
4 | 232030003023132203111 |
5 | 404000410222001432 |
6 | 10430044155452405 |
7 | 445213345212014 |
oct | 56140313364325 |
9 | 12212656236315 |
10 | 3174034172117 |
11 | 10141115a8096 |
12 | 433195757105 |
13 | 1a04054b1683 |
14 | ad8a465aa7b |
15 | 5786d3147b2 |
hex | 2e3032de8d5 |
3174034172117 has 2 divisors, whose sum is σ = 3174034172118. Its totient is φ = 3174034172116.
The previous prime is 3174034172107. The next prime is 3174034172123. The reversal of 3174034172117 is 7112714304713.
3174034172117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3143355248401 + 30678923716 = 1772951^2 + 175154^2 .
It is a cyclic number.
It is not a de Polignac number, because 3174034172117 - 218 = 3174033909973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3174034172107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1587017086058 + 1587017086059.
It is an arithmetic number, because the mean of its divisors is an integer number (1587017086059).
Almost surely, 23174034172117 is an apocalyptic number.
It is an amenable number.
3174034172117 is a deficient number, since it is larger than the sum of its proper divisors (1).
3174034172117 is an equidigital number, since it uses as much as digits as its factorization.
3174034172117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 98784, while the sum is 41.
The spelling of 3174034172117 in words is "three trillion, one hundred seventy-four billion, thirty-four million, one hundred seventy-two thousand, one hundred seventeen".
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