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317506306153 is a prime number
BaseRepresentation
bin1001001111011001101…
…10011100000001101001
31010100112120010112010111
410213230312130001221
520200223103244103
6401505502014321
731640050033651
oct4475466340151
91110476115114
10317506306153
1111272103a213
12516502773a1
1323c2c9a454a
1411520179361
1583d454786d
hex49ecd9c069

317506306153 has 2 divisors, whose sum is σ = 317506306154. Its totient is φ = 317506306152.

The previous prime is 317506306151. The next prime is 317506306259. The reversal of 317506306153 is 351603605713.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 214713610384 + 102792695769 = 463372^2 + 320613^2 .

It is an emirp because it is prime and its reverse (351603605713) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 317506306153 - 21 = 317506306151 is a prime.

Together with 317506306151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (317506306151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158753153076 + 158753153077.

It is an arithmetic number, because the mean of its divisors is an integer number (158753153077).

Almost surely, 2317506306153 is an apocalyptic number.

It is an amenable number.

317506306153 is a deficient number, since it is larger than the sum of its proper divisors (1).

317506306153 is an equidigital number, since it uses as much as digits as its factorization.

317506306153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 170100, while the sum is 40.

The spelling of 317506306153 in words is "three hundred seventeen billion, five hundred six million, three hundred six thousand, one hundred fifty-three".