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31981168023157 is a prime number
BaseRepresentation
bin1110100010110001100100…
…01010001101011001110101
311012020100222120212001202101
413101120302022031121311
513142434413003220112
6152003540141342101
76510364104624553
oct721306212153165
9135210876761671
1031981168023157
11a210156668a11
1237061b8567931
1314aca712a5452
147c7c7ab1cbd3
153a6d8485b757
hex1d163228d675

31981168023157 has 2 divisors, whose sum is σ = 31981168023158. Its totient is φ = 31981168023156.

The previous prime is 31981168023053. The next prime is 31981168023191. The reversal of 31981168023157 is 75132086118913.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28779265766161 + 3201902256996 = 5364631^2 + 1789386^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31981168023157 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31981168023098 and 31981168023107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31981168023757) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15990584011578 + 15990584011579.

It is an arithmetic number, because the mean of its divisors is an integer number (15990584011579).

Almost surely, 231981168023157 is an apocalyptic number.

It is an amenable number.

31981168023157 is a deficient number, since it is larger than the sum of its proper divisors (1).

31981168023157 is an equidigital number, since it uses as much as digits as its factorization.

31981168023157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 55.

The spelling of 31981168023157 in words is "thirty-one trillion, nine hundred eighty-one billion, one hundred sixty-eight million, twenty-three thousand, one hundred fifty-seven".