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31990014443 is a prime number
BaseRepresentation
bin11101110010110000…
…001110000111101011
310001120102212002222202
4131302300032013223
51011003420430233
622410201010415
72211512431142
oct356260160753
9101512762882
1031990014443
1112626590372
126249483a0b
13302a75433a
141796864759
15c736b7be8
hex772c0e1eb

31990014443 has 2 divisors, whose sum is σ = 31990014444. Its totient is φ = 31990014442.

The previous prime is 31990014437. The next prime is 31990014467. The reversal of 31990014443 is 34441009913.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (34441009913) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31990014443 - 28 = 31990014187 is a prime.

It is a super-2 number, since 2×319900144432 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31990014397 and 31990014406.

It is not a weakly prime, because it can be changed into another prime (31990014403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15995007221 + 15995007222.

It is an arithmetic number, because the mean of its divisors is an integer number (15995007222).

Almost surely, 231990014443 is an apocalyptic number.

31990014443 is a deficient number, since it is larger than the sum of its proper divisors (1).

31990014443 is an equidigital number, since it uses as much as digits as its factorization.

31990014443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46656, while the sum is 38.

The spelling of 31990014443 in words is "thirty-one billion, nine hundred ninety million, fourteen thousand, four hundred forty-three".