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3200113471 is a prime number
BaseRepresentation
bin1011111010111101…
…1101101100111111
322021000120121102011
42332233131230333
523023212112341
61245313312051
7142205341612
oct27657355477
98230517364
103200113471
1113a2420685
12753865627
133bccab389
14225018179
1513ae21b81
hexbebddb3f

3200113471 has 2 divisors, whose sum is σ = 3200113472. Its totient is φ = 3200113470.

The previous prime is 3200113417. The next prime is 3200113481. The reversal of 3200113471 is 1743110023.

Together with previous prime (3200113417) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3200113471 - 217 = 3199982399 is a prime.

It is a super-3 number, since 3×32001134713 (a number of 29 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3200113481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600056735 + 1600056736.

It is an arithmetic number, because the mean of its divisors is an integer number (1600056736).

Almost surely, 23200113471 is an apocalyptic number.

3200113471 is a deficient number, since it is larger than the sum of its proper divisors (1).

3200113471 is an equidigital number, since it uses as much as digits as its factorization.

3200113471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 22.

The square root of 3200113471 is about 56569.5454374525. The cubic root of 3200113471 is about 1473.6300171977.

Adding to 3200113471 its reverse (1743110023), we get a palindrome (4943223494).

The spelling of 3200113471 in words is "three billion, two hundred million, one hundred thirteen thousand, four hundred seventy-one".