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320013033300022 = 2160006516650011
BaseRepresentation
bin100100011000011001101011…
…1001011000110000000110110
31112222001221120111212100000111
41020300303113023012000312
5313421043143011100042
63052335542531133234
7124256115200651146
oct11060632713060066
91488057514770014
10320013033300022
1192a69846636797
122ba8480544421a
131097413a9495aa
1459049dba0a926
1526ee417a23517
hex1230cd72c6036

320013033300022 has 4 divisors (see below), whose sum is σ = 480019549950036. Its totient is φ = 160006516650010.

The previous prime is 320013033300001. The next prime is 320013033300073. The reversal of 320013033300022 is 220003330310023.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 320013033299966 and 320013033300002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80003258325004 + ... + 80003258325007.

It is an arithmetic number, because the mean of its divisors is an integer number (120004887487509).

Almost surely, 2320013033300022 is an apocalyptic number.

320013033300022 is a deficient number, since it is larger than the sum of its proper divisors (160006516650014).

320013033300022 is a wasteful number, since it uses less digits than its factorization.

320013033300022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 160006516650013.

The product of its (nonzero) digits is 1944, while the sum is 22.

Adding to 320013033300022 its reverse (220003330310023), we get a palindrome (540016363610045).

The spelling of 320013033300022 in words is "three hundred twenty trillion, thirteen billion, thirty-three million, three hundred thousand, twenty-two".

Divisors: 1 2 160006516650011 320013033300022