Base | Representation |
---|---|
bin | 1110100011011100110111… |
… | …00100110011101110010111 |
3 | 11012022120222110102222111201 |
4 | 13101232123210303232113 |
5 | 13143330013312040043 |
6 | 152022342412413331 |
7 | 6512146102460401 |
oct | 721563344635627 |
9 | 135276873388451 |
10 | 32004411440023 |
11 | a219aa39a5040 |
12 | 370a804777247 |
13 | 14b2006910759 |
14 | 7c9043a91b71 |
15 | 3a77951eec4d |
hex | 1d1b9b933b97 |
32004411440023 has 32 divisors (see below), whose sum is σ = 36245844817920. Its totient is φ = 27995718960000.
The previous prime is 32004411439993. The next prime is 32004411440107.
32004411440023 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 32004411440023 - 25 = 32004411439991 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 32004411439973 and 32004411440000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32004411440623) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 604320661 + ... + 604373617.
It is an arithmetic number, because the mean of its divisors is an integer number (1132682650560).
Almost surely, 232004411440023 is an apocalyptic number.
32004411440023 is a deficient number, since it is larger than the sum of its proper divisors (4241433377897).
32004411440023 is a wasteful number, since it uses less digits than its factorization.
32004411440023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63079.
The product of its (nonzero) digits is 9216, while the sum is 28.
It can be divided in two parts, 3200441 and 1440023, that added together give a palindrome (4640464).
The spelling of 32004411440023 in words is "thirty-two trillion, four billion, four hundred eleven million, four hundred forty thousand, twenty-three".
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