Base | Representation |
---|---|
bin | 100100011000101101111111… |
… | …1100011010111011101100111 |
3 | 1112222020010011221222212222111 |
4 | 1020301123333203113131213 |
5 | 313422302020032041201 |
6 | 3052411555555541451 |
7 | 124262221260255061 |
oct | 11061337743273547 |
9 | 1488203157885874 |
10 | 320056660424551 |
11 | 92a862a3a4a106 |
12 | 2ba9115bbba887 |
13 | 109782a12b818b |
14 | 5906b79bc8731 |
15 | 270061cb78b51 |
hex | 12316ff8d7767 |
320056660424551 has 2 divisors, whose sum is σ = 320056660424552. Its totient is φ = 320056660424550.
The previous prime is 320056660424531. The next prime is 320056660424569. The reversal of 320056660424551 is 155424066650023.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 320056660424551 - 213 = 320056660416359 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 320056660424495 and 320056660424504.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (320056660424531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160028330212275 + 160028330212276.
It is an arithmetic number, because the mean of its divisors is an integer number (160028330212276).
Almost surely, 2320056660424551 is an apocalyptic number.
320056660424551 is a deficient number, since it is larger than the sum of its proper divisors (1).
320056660424551 is an equidigital number, since it uses as much as digits as its factorization.
320056660424551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184000, while the sum is 49.
The spelling of 320056660424551 in words is "three hundred twenty trillion, fifty-six billion, six hundred sixty million, four hundred twenty-four thousand, five hundred fifty-one".
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