Base | Representation |
---|---|
bin | 101110100101010010010… |
… | …011001111011111100111 |
3 | 102100000200100111121122121 |
4 | 232211102103033133213 |
5 | 404421404120131211 |
6 | 10450325055410411 |
7 | 450163010021512 |
oct | 56452223173747 |
9 | 12300610447577 |
10 | 3201131411431 |
11 | 1024657257048 |
12 | 438498523a07 |
13 | 1a2b3337a2a5 |
14 | b0d15371d79 |
15 | 584071a6271 |
hex | 2e9524cf7e7 |
3201131411431 has 2 divisors, whose sum is σ = 3201131411432. Its totient is φ = 3201131411430.
The previous prime is 3201131411329. The next prime is 3201131411441. The reversal of 3201131411431 is 1341141311023.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3201131411431 is a prime.
It is a super-2 number, since 2×32011314114312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3201131411396 and 3201131411405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3201131411441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600565705715 + 1600565705716.
It is an arithmetic number, because the mean of its divisors is an integer number (1600565705716).
Almost surely, 23201131411431 is an apocalyptic number.
3201131411431 is a deficient number, since it is larger than the sum of its proper divisors (1).
3201131411431 is an equidigital number, since it uses as much as digits as its factorization.
3201131411431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 3201131411431 its reverse (1341141311023), we get a palindrome (4542272722454).
The spelling of 3201131411431 in words is "three trillion, two hundred one billion, one hundred thirty-one million, four hundred eleven thousand, four hundred thirty-one".
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