Base | Representation |
---|---|
bin | 1001010100010000011… |
… | …11110101111011100111 |
3 | 1010121021020220100122211 |
4 | 10222020033311323213 |
5 | 20221043014344333 |
6 | 403020313504251 |
7 | 32061465203533 |
oct | 4521017657347 |
9 | 1117236810584 |
10 | 320113434343 |
11 | 11383976320a |
12 | 52059412087 |
13 | 24256b71b51 |
14 | 116ca514bc3 |
15 | 84d8384ecd |
hex | 4a883f5ee7 |
320113434343 has 4 divisors (see below), whose sum is σ = 320120771608. Its totient is φ = 320106097080.
The previous prime is 320113434271. The next prime is 320113434349. The reversal of 320113434343 is 343434311023.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-320113434343 is a prime.
It is a super-2 number, since 2×3201134343432 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (320113434349) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3602796 + ... + 3690577.
It is an arithmetic number, because the mean of its divisors is an integer number (80030192902).
Almost surely, 2320113434343 is an apocalyptic number.
320113434343 is a deficient number, since it is larger than the sum of its proper divisors (7337265).
320113434343 is an equidigital number, since it uses as much as digits as its factorization.
320113434343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7337264.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 320113434343 its reverse (343434311023), we get a palindrome (663547745366).
The spelling of 320113434343 in words is "three hundred twenty billion, one hundred thirteen million, four hundred thirty-four thousand, three hundred forty-three".
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