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32012131999 = 285731120363
BaseRepresentation
bin11101110100000100…
…100101111010011111
310001121222110210120111
4131310010211322133
51011030101210444
622412311030451
72212201426621
oct356404457237
9101558423514
1032012131999
1112638017641
12625496b427
1330321c9553
141799780c11
15c755d6234
hex774125e9f

32012131999 has 4 divisors (see below), whose sum is σ = 32013280936. Its totient is φ = 32010983064.

The previous prime is 32012131993. The next prime is 32012132003. The reversal of 32012131999 is 99913121023.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 99913121023 = 195258585317.

It is a cyclic number.

It is not a de Polignac number, because 32012131999 - 217 = 32012000927 is a prime.

It is a super-3 number, since 3×320121319993 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32012131993) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 531609 + ... + 588754.

It is an arithmetic number, because the mean of its divisors is an integer number (8003320234).

Almost surely, 232012131999 is an apocalyptic number.

32012131999 is a deficient number, since it is larger than the sum of its proper divisors (1148937).

32012131999 is a wasteful number, since it uses less digits than its factorization.

32012131999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1148936.

The product of its (nonzero) digits is 26244, while the sum is 40.

The spelling of 32012131999 in words is "thirty-two billion, twelve million, one hundred thirty-one thousand, nine hundred ninety-nine".

Divisors: 1 28573 1120363 32012131999