Base | Representation |
---|---|
bin | 101110100101010111001… |
… | …011001111011001111111 |
3 | 102100000220001101220110211 |
4 | 232211113023033121333 |
5 | 404422041034344444 |
6 | 10450341140413251 |
7 | 450165022144243 |
oct | 56452713173177 |
9 | 12300801356424 |
10 | 3201213199999 |
11 | 102469943a001 |
12 | 4384bb9a7227 |
13 | 1a2b472b57a9 |
14 | b0d22182423 |
15 | 5840e45ec34 |
hex | 2e9572cf67f |
3201213199999 has 4 divisors (see below), whose sum is σ = 3201218977240. Its totient is φ = 3201207422760.
The previous prime is 3201213199993. The next prime is 3201213200023. The reversal of 3201213199999 is 9999913121023.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3201213199999 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3201213199993) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1957389 + ... + 3199030.
It is an arithmetic number, because the mean of its divisors is an integer number (800304744310).
Almost surely, 23201213199999 is an apocalyptic number.
3201213199999 is a deficient number, since it is larger than the sum of its proper divisors (5777241).
3201213199999 is an equidigital number, since it uses as much as digits as its factorization.
3201213199999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5777240.
The product of its (nonzero) digits is 2125764, while the sum is 58.
The spelling of 3201213199999 in words is "three trillion, two hundred one billion, two hundred thirteen million, one hundred ninety-nine thousand, nine hundred ninety-nine".
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