Base | Representation |
---|---|
bin | 101110100101011001000… |
… | …000110110100110101001 |
3 | 102100000222012102022012121 |
4 | 232211121000312212221 |
5 | 404422121433001101 |
6 | 10450344201311241 |
7 | 450165545204563 |
oct | 56453100664651 |
9 | 12300865368177 |
10 | 3201244031401 |
11 | 10247048880a9 |
12 | 43850a195521 |
13 | 1a2b507bc020 |
14 | b0d262ca333 |
15 | 584120000a1 |
hex | 2e9590369a9 |
3201244031401 has 4 divisors (see below), whose sum is σ = 3447493572292. Its totient is φ = 2954994490512.
The previous prime is 3201244031399. The next prime is 3201244031417. The reversal of 3201244031401 is 1041304421023.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1336104810000 + 1865139221401 = 1155900^2 + 1365701^2 .
It is a cyclic number.
It is not a de Polignac number, because 3201244031401 - 21 = 3201244031399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3201244031201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123124770426 + ... + 123124770451.
It is an arithmetic number, because the mean of its divisors is an integer number (861873393073).
Almost surely, 23201244031401 is an apocalyptic number.
It is an amenable number.
3201244031401 is a deficient number, since it is larger than the sum of its proper divisors (246249540891).
3201244031401 is a wasteful number, since it uses less digits than its factorization.
3201244031401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 246249540890.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 3201244031401 its reverse (1041304421023), we get a palindrome (4242548452424).
The spelling of 3201244031401 in words is "three trillion, two hundred one billion, two hundred forty-four million, thirty-one thousand, four hundred one".
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