Base | Representation |
---|---|
bin | 11101110100001000… |
… | …010101101011111101 |
3 | 10001122001022200202221 |
4 | 131310020111223331 |
5 | 1011030324122414 |
6 | 22412344045341 |
7 | 2212212660124 |
oct | 356410255375 |
9 | 101561280687 |
10 | 32013114109 |
11 | 126386284a9 |
12 | 6255163851 |
13 | 3032481592 |
14 | 1799958abb |
15 | c7572c224 |
hex | 774215afd |
32013114109 has 2 divisors, whose sum is σ = 32013114110. Its totient is φ = 32013114108.
The previous prime is 32013114097. The next prime is 32013114149. The reversal of 32013114109 is 90141131023.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29858112025 + 2155002084 = 172795^2 + 46422^2 .
It is an emirp because it is prime and its reverse (90141131023) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 32013114109 - 27 = 32013113981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32013114149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16006557054 + 16006557055.
It is an arithmetic number, because the mean of its divisors is an integer number (16006557055).
Almost surely, 232013114109 is an apocalyptic number.
It is an amenable number.
32013114109 is a deficient number, since it is larger than the sum of its proper divisors (1).
32013114109 is an equidigital number, since it uses as much as digits as its factorization.
32013114109 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 32013114109 in words is "thirty-two billion, thirteen million, one hundred fourteen thousand, one hundred nine".
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