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32013121341 = 310671040447
BaseRepresentation
bin11101110100001000…
…010111011100111101
310001122001100001200210
4131310020113130331
51011030324340331
622412344143033
72212213020165
oct356410273475
9101561301623
1032013121341
1112638632983
126255167a79
133032484966
14179995b5a5
15c7572e446
hex77421773d

32013121341 has 4 divisors (see below), whose sum is σ = 42684161792. Its totient is φ = 21342080892.

The previous prime is 32013121339. The next prime is 32013121351. The reversal of 32013121341 is 14312131023.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 32013121341 - 21 = 32013121339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32013121351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5335520221 + ... + 5335520226.

It is an arithmetic number, because the mean of its divisors is an integer number (10671040448).

Almost surely, 232013121341 is an apocalyptic number.

It is an amenable number.

32013121341 is a deficient number, since it is larger than the sum of its proper divisors (10671040451).

32013121341 is a wasteful number, since it uses less digits than its factorization.

32013121341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10671040450.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 32013121341 its reverse (14312131023), we get a palindrome (46325252364).

The spelling of 32013121341 in words is "thirty-two billion, thirteen million, one hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 3 10671040447 32013121341