Base | Representation |
---|---|
bin | 11101110100001000… |
… | …101101110111001011 |
3 | 10001122001111201121102 |
4 | 131310020231313023 |
5 | 1011030340310011 |
6 | 22412350132015 |
7 | 2212213551614 |
oct | 356410556713 |
9 | 101561451542 |
10 | 32013213131 |
11 | 12638695939 |
12 | 62551b100b |
13 | 30324b7683 |
14 | 1799982c0b |
15 | c7574b73b |
hex | 77422ddcb |
32013213131 has 4 divisors (see below), whose sum is σ = 32019676272. Its totient is φ = 32006749992.
The previous prime is 32013213121. The next prime is 32013213139. The reversal of 32013213131 is 13131231023.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13131231023 = 7529 ⋅1744087.
It is a cyclic number.
It is not a de Polignac number, because 32013213131 - 222 = 32009018827 is a prime.
It is a super-2 number, since 2×320132131312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32013213139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3224135 + ... + 3234048.
It is an arithmetic number, because the mean of its divisors is an integer number (8004919068).
Almost surely, 232013213131 is an apocalyptic number.
32013213131 is a deficient number, since it is larger than the sum of its proper divisors (6463141).
32013213131 is an equidigital number, since it uses as much as digits as its factorization.
32013213131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6463140.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 32013213131 its reverse (13131231023), we get a palindrome (45144444154).
The spelling of 32013213131 in words is "thirty-two billion, thirteen million, two hundred thirteen thousand, one hundred thirty-one".
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