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3201354145799 is a prime number
BaseRepresentation
bin101110100101011111100…
…100111010000000000111
3102100001020212121200202122
4232211133210322000013
5404422333130131144
610450403133400155
7450201353154035
oct56453744720007
912301225550678
103201354145799
111024760a57737
1243853b03905b
131a2b6a564484
14b0d36b91555
155841ba017ee
hex2e95f93a007

3201354145799 has 2 divisors, whose sum is σ = 3201354145800. Its totient is φ = 3201354145798.

The previous prime is 3201354145727. The next prime is 3201354145831. The reversal of 3201354145799 is 9975414531023.

3201354145799 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (9975414531023) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3201354145799 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3201354145799.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3201354144799) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600677072899 + 1600677072900.

It is an arithmetic number, because the mean of its divisors is an integer number (1600677072900).

Almost surely, 23201354145799 is an apocalyptic number.

3201354145799 is a deficient number, since it is larger than the sum of its proper divisors (1).

3201354145799 is an equidigital number, since it uses as much as digits as its factorization.

3201354145799 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4082400, while the sum is 53.

The spelling of 3201354145799 in words is "three trillion, two hundred one billion, three hundred fifty-four million, one hundred forty-five thousand, seven hundred ninety-nine".