Base | Representation |
---|---|
bin | 101110100101101111011… |
… | …101011110101100111111 |
3 | 102100001221110001201102222 |
4 | 232211233131132230333 |
5 | 404423404340300211 |
6 | 10450445413235555 |
7 | 450211100241602 |
oct | 56455735365477 |
9 | 12301843051388 |
10 | 3201620634431 |
11 | 102488842257a |
12 | 4385b4332bbb |
13 | 1a2bb082ac5b |
14 | b0d60320339 |
15 | 584350e11db |
hex | 2e96f75eb3f |
3201620634431 has 4 divisors (see below), whose sum is σ = 3254106218664. Its totient is φ = 3149135050200.
The previous prime is 3201620634413. The next prime is 3201620634461. The reversal of 3201620634431 is 1344360261023.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3201620634431 is a prime.
It is a super-3 number, since 3×32016206344313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3201620634391 and 3201620634400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3201620634461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26242792025 + ... + 26242792146.
It is an arithmetic number, because the mean of its divisors is an integer number (813526554666).
Almost surely, 23201620634431 is an apocalyptic number.
3201620634431 is a deficient number, since it is larger than the sum of its proper divisors (52485584233).
3201620634431 is an equidigital number, since it uses as much as digits as its factorization.
3201620634431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52485584232.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 3201620634431 its reverse (1344360261023), we get a palindrome (4545980895454).
The spelling of 3201620634431 in words is "three trillion, two hundred one billion, six hundred twenty million, six hundred thirty-four thousand, four hundred thirty-one".
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