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32020201113 = 310673400371
BaseRepresentation
bin11101110100100011…
…010111111010011001
310001122112122202022120
4131310203113322121
51011034132413423
622413200011453
72212330135005
oct356443277231
9101575582276
1032020201113
111264162902a
126257600b89
133033a93284
14179a881705
15c7617bee3
hex7748d7e99

32020201113 has 4 divisors (see below), whose sum is σ = 42693601488. Its totient is φ = 21346800740.

The previous prime is 32020201099. The next prime is 32020201133. The reversal of 32020201113 is 31110202023.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32020201113 - 26 = 32020201049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32020201092 and 32020201101.

It is not an unprimeable number, because it can be changed into a prime (32020201133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5336700183 + ... + 5336700188.

It is an arithmetic number, because the mean of its divisors is an integer number (10673400372).

Almost surely, 232020201113 is an apocalyptic number.

It is an amenable number.

32020201113 is a deficient number, since it is larger than the sum of its proper divisors (10673400375).

32020201113 is a wasteful number, since it uses less digits than its factorization.

32020201113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10673400374.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 32020201113 its reverse (31110202023), we get a palindrome (63130403136).

The spelling of 32020201113 in words is "thirty-two billion, twenty million, two hundred one thousand, one hundred thirteen".

Divisors: 1 3 10673400371 32020201113