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320211132000217 is a prime number
BaseRepresentation
bin100100011001110101111011…
…0110001101010011111011001
31112222202212220100111222111121
41020303223312301222133121
5313432314344243001332
63053010544021525241
7124306330234063063
oct11063536661523731
91488685810458447
10320211132000217
1193035862144237
122bab7090273821
1310989a1b09b3a3
1459104313a6733
15270465e0ce797
hex1233af6c6a7d9

320211132000217 has 2 divisors, whose sum is σ = 320211132000218. Its totient is φ = 320211132000216.

The previous prime is 320211132000173. The next prime is 320211132000251. The reversal of 320211132000217 is 712000231112023.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 318602651109136 + 1608480891081 = 17849444^2 + 1268259^2 .

It is a cyclic number.

It is not a de Polignac number, because 320211132000217 - 211 = 320211131998169 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 320211132000191 and 320211132000200.

It is not a weakly prime, because it can be changed into another prime (320211132000517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160105566000108 + 160105566000109.

It is an arithmetic number, because the mean of its divisors is an integer number (160105566000109).

Almost surely, 2320211132000217 is an apocalyptic number.

It is an amenable number.

320211132000217 is a deficient number, since it is larger than the sum of its proper divisors (1).

320211132000217 is an equidigital number, since it uses as much as digits as its factorization.

320211132000217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

The spelling of 320211132000217 in words is "three hundred twenty trillion, two hundred eleven billion, one hundred thirty-two million, two hundred seventeen", and thus it is an aban number.