Base | Representation |
---|---|
bin | 100100011001110101111011… |
… | …0110001101010011111111011 |
3 | 1112222202212220100111222112212 |
4 | 1020303223312301222133323 |
5 | 313432314344243002001 |
6 | 3053010544021525335 |
7 | 124306330234063142 |
oct | 11063536661523773 |
9 | 1488685810458485 |
10 | 320211132000251 |
11 | 93035862144268 |
12 | 2bab709027384b |
13 | 10989a1b09b3cb |
14 | 59104313a6759 |
15 | 270465e0ce7bb |
hex | 1233af6c6a7fb |
320211132000251 has 2 divisors, whose sum is σ = 320211132000252. Its totient is φ = 320211132000250.
The previous prime is 320211132000217. The next prime is 320211132000311. The reversal of 320211132000251 is 152000231112023.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 320211132000251 - 214 = 320211131983867 is a prime.
It is not a weakly prime, because it can be changed into another prime (320211132900251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160105566000125 + 160105566000126.
It is an arithmetic number, because the mean of its divisors is an integer number (160105566000126).
Almost surely, 2320211132000251 is an apocalyptic number.
320211132000251 is a deficient number, since it is larger than the sum of its proper divisors (1).
320211132000251 is an equidigital number, since it uses as much as digits as its factorization.
320211132000251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 320211132000251 its reverse (152000231112023), we get a palindrome (472211363112274).
The spelling of 320211132000251 in words is "three hundred twenty trillion, two hundred eleven billion, one hundred thirty-two million, two hundred fifty-one", and thus it is an aban number.
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