Base | Representation |
---|---|
bin | 100100011001111111011011… |
… | …0110001010110010111100011 |
3 | 1112222211211120010121210010022 |
4 | 1020303332312301112113203 |
5 | 313433133134422344301 |
6 | 3053024200234224055 |
7 | 124310651625605624 |
oct | 11063766661262743 |
9 | 1488754503553108 |
10 | 320231533012451 |
11 | 93043480a6a725 |
12 | 2babb02458502b |
13 | 1098b91c880268 |
14 | 5911408a37a4b |
15 | 2704e5515dd1b |
hex | 1233fb6c565e3 |
320231533012451 has 2 divisors, whose sum is σ = 320231533012452. Its totient is φ = 320231533012450.
The previous prime is 320231533012441. The next prime is 320231533012453. The reversal of 320231533012451 is 154210335132023.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 320231533012451 - 218 = 320231532750307 is a prime.
Together with 320231533012453, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (320231533012453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160115766506225 + 160115766506226.
It is an arithmetic number, because the mean of its divisors is an integer number (160115766506226).
Almost surely, 2320231533012451 is an apocalyptic number.
320231533012451 is a deficient number, since it is larger than the sum of its proper divisors (1).
320231533012451 is an equidigital number, since it uses as much as digits as its factorization.
320231533012451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 320231533012451 its reverse (154210335132023), we get a palindrome (474441868144474).
The spelling of 320231533012451 in words is "three hundred twenty trillion, two hundred thirty-one billion, five hundred thirty-three million, twelve thousand, four hundred fifty-one".
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