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320544113 is a prime number
BaseRepresentation
bin10011000110110…
…001110101110001
3211100011022212012
4103012301311301
51124024402423
651450212305
710641402641
oct2306616561
9740138765
10320544113
11154a3659a
128b424095
1351541a96
1430800521
151d21b078
hex131b1d71

320544113 has 2 divisors, whose sum is σ = 320544114. Its totient is φ = 320544112.

The previous prime is 320544101. The next prime is 320544149. The reversal of 320544113 is 311445023.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 282004849 + 38539264 = 16793^2 + 6208^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-320544113 is a prime.

It is a super-5 number, since 5×3205441135 (a number of 44 digits) contains 55555 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (320544173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160272056 + 160272057.

It is an arithmetic number, because the mean of its divisors is an integer number (160272057).

Almost surely, 2320544113 is an apocalyptic number.

It is an amenable number.

320544113 is a deficient number, since it is larger than the sum of its proper divisors (1).

320544113 is an equidigital number, since it uses as much as digits as its factorization.

320544113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 320544113 is about 17903.7457812604. The cubic root of 320544113 is about 684.3778342091.

Adding to 320544113 its reverse (311445023), we get a palindrome (631989136).

The spelling of 320544113 in words is "three hundred twenty million, five hundred forty-four thousand, one hundred thirteen".