Base | Representation |
---|---|
bin | 1110100110001111001001… |
… | …11111010011110001111001 |
3 | 11012122202001102022210022112 |
4 | 13103013210333103301321 |
5 | 13201412032343414340 |
6 | 152134333001102105 |
7 | 6522105130316255 |
oct | 723074477236171 |
9 | 135582042283275 |
10 | 32100132404345 |
11 | a256653991315 |
12 | 3725279487935 |
13 | 14bb04ca61005 |
14 | 7cd9246c5265 |
15 | 3a9ee8947065 |
hex | 1d31e4fd3c79 |
32100132404345 has 4 divisors (see below), whose sum is σ = 38520158885220. Its totient is φ = 25680105923472.
The previous prime is 32100132404293. The next prime is 32100132404429. The reversal of 32100132404345 is 54340423100123.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 14100002470009 + 18000129934336 = 3754997^2 + 4242656^2 .
It is a cyclic number.
It is not a de Polignac number, because 32100132404345 - 210 = 32100132403321 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3210013240430 + ... + 3210013240439.
It is an arithmetic number, because the mean of its divisors is an integer number (9630039721305).
Almost surely, 232100132404345 is an apocalyptic number.
It is an amenable number.
32100132404345 is a deficient number, since it is larger than the sum of its proper divisors (6420026480875).
32100132404345 is an equidigital number, since it uses as much as digits as its factorization.
32100132404345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6420026480874.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 32100132404345 its reverse (54340423100123), we get a palindrome (86440555504468).
The spelling of 32100132404345 in words is "thirty-two trillion, one hundred billion, one hundred thirty-two million, four hundred four thousand, three hundred forty-five".
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