Base | Representation |
---|---|
bin | 100100011111100111001111… |
… | …1010111010001000000010011 |
3 | 1120002120201001000121221022212 |
4 | 1020333032133113101000103 |
5 | 314033313133002141201 |
6 | 3054415150503022335 |
7 | 124420535114254451 |
oct | 11077163727210023 |
9 | 1502521030557285 |
10 | 321004234412051 |
11 | 93311149842943 |
12 | 3000493073a9ab |
13 | 10a1675301b338 |
14 | 593a98b62d9d1 |
15 | 271a0cba86abb |
hex | 123f39f5d1013 |
321004234412051 has 2 divisors, whose sum is σ = 321004234412052. Its totient is φ = 321004234412050.
The previous prime is 321004234412039. The next prime is 321004234412053. The reversal of 321004234412051 is 150214432400123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 321004234412051 - 214 = 321004234395667 is a prime.
Together with 321004234412053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 321004234411999 and 321004234412017.
It is not a weakly prime, because it can be changed into another prime (321004234412053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160502117206025 + 160502117206026.
It is an arithmetic number, because the mean of its divisors is an integer number (160502117206026).
Almost surely, 2321004234412051 is an apocalyptic number.
321004234412051 is a deficient number, since it is larger than the sum of its proper divisors (1).
321004234412051 is an equidigital number, since it uses as much as digits as its factorization.
321004234412051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 321004234412051 its reverse (150214432400123), we get a palindrome (471218666812174).
The spelling of 321004234412051 in words is "three hundred twenty-one trillion, four billion, two hundred thirty-four million, four hundred twelve thousand, fifty-one".
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