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321004234412051 is a prime number
BaseRepresentation
bin100100011111100111001111…
…1010111010001000000010011
31120002120201001000121221022212
41020333032133113101000103
5314033313133002141201
63054415150503022335
7124420535114254451
oct11077163727210023
91502521030557285
10321004234412051
1193311149842943
123000493073a9ab
1310a1675301b338
14593a98b62d9d1
15271a0cba86abb
hex123f39f5d1013

321004234412051 has 2 divisors, whose sum is σ = 321004234412052. Its totient is φ = 321004234412050.

The previous prime is 321004234412039. The next prime is 321004234412053. The reversal of 321004234412051 is 150214432400123.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 321004234412051 - 214 = 321004234395667 is a prime.

Together with 321004234412053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 321004234411999 and 321004234412017.

It is not a weakly prime, because it can be changed into another prime (321004234412053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160502117206025 + 160502117206026.

It is an arithmetic number, because the mean of its divisors is an integer number (160502117206026).

Almost surely, 2321004234412051 is an apocalyptic number.

321004234412051 is a deficient number, since it is larger than the sum of its proper divisors (1).

321004234412051 is an equidigital number, since it uses as much as digits as its factorization.

321004234412051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 321004234412051 its reverse (150214432400123), we get a palindrome (471218666812174).

The spelling of 321004234412051 in words is "three hundred twenty-one trillion, four billion, two hundred thirty-four million, four hundred twelve thousand, fifty-one".