Base | Representation |
---|---|
bin | 1110100110001111101110… |
… | …11001110011110010100101 |
3 | 11012122202211221122101212022 |
4 | 13103013313121303302211 |
5 | 13201413200440403333 |
6 | 152134423354432525 |
7 | 6522115601246426 |
oct | 723076731636245 |
9 | 135582757571768 |
10 | 32100441341093 |
11 | a2567a230a044 |
12 | 3725344a32745 |
13 | 14bb09ba6a718 |
14 | 7cd95374364d |
15 | 3aa015b1dc98 |
hex | 1d31f7673ca5 |
32100441341093 has 2 divisors, whose sum is σ = 32100441341094. Its totient is φ = 32100441341092.
The previous prime is 32100441341083. The next prime is 32100441341123. The reversal of 32100441341093 is 39014314400123.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22238033981284 + 9862407359809 = 4715722^2 + 3140447^2 .
It is a cyclic number.
It is not a de Polignac number, because 32100441341093 - 230 = 32099367599269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32100441341083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16050220670546 + 16050220670547.
It is an arithmetic number, because the mean of its divisors is an integer number (16050220670547).
Almost surely, 232100441341093 is an apocalyptic number.
It is an amenable number.
32100441341093 is a deficient number, since it is larger than the sum of its proper divisors (1).
32100441341093 is an equidigital number, since it uses as much as digits as its factorization.
32100441341093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 32100441341093 in words is "thirty-two trillion, one hundred billion, four hundred forty-one million, three hundred forty-one thousand, ninety-three".
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