Base | Representation |
---|---|
bin | 1110100110010001010110… |
… | …01011011110111101101001 |
3 | 11012122212002111011220020111 |
4 | 13103020223023132331221 |
5 | 13201421440330013001 |
6 | 152135045505054321 |
7 | 6522146246605543 |
oct | 723105313367551 |
9 | 135585074156214 |
10 | 32101310001001 |
11 | a2570a868609a |
12 | 37255479273a1 |
13 | 14bb1a9a10177 |
14 | 7cd9d6c62693 |
15 | 3aa067009851 |
hex | 1d322b2def69 |
32101310001001 has 2 divisors, whose sum is σ = 32101310001002. Its totient is φ = 32101310001000.
The previous prime is 32101310000993. The next prime is 32101310001011. The reversal of 32101310001001 is 10010001310123.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16502159421225 + 15599150579776 = 4062285^2 + 3949576^2 .
It is a cyclic number.
It is not a de Polignac number, because 32101310001001 - 23 = 32101310000993 is a prime.
It is not a weakly prime, because it can be changed into another prime (32101310001011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16050655000500 + 16050655000501.
It is an arithmetic number, because the mean of its divisors is an integer number (16050655000501).
Almost surely, 232101310001001 is an apocalyptic number.
It is an amenable number.
32101310001001 is a deficient number, since it is larger than the sum of its proper divisors (1).
32101310001001 is an equidigital number, since it uses as much as digits as its factorization.
32101310001001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 32101310001001 its reverse (10010001310123), we get a palindrome (42111311311124).
The spelling of 32101310001001 in words is "thirty-two trillion, one hundred one billion, three hundred ten million, one thousand, one".
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