Base | Representation |
---|---|
bin | 101110101101110000101… |
… | …001010101001101111001 |
3 | 102100220011110221211022101 |
4 | 232231300221111031321 |
5 | 410044022443444423 |
6 | 10454432015423401 |
7 | 450634334424025 |
oct | 56556051251571 |
9 | 12326143854271 |
10 | 3210230453113 |
11 | 10284a6444802 |
12 | 43a1b7824b61 |
13 | 1a39534c6b18 |
14 | b15399a9385 |
15 | 5878ade87ad |
hex | 2eb70a55379 |
3210230453113 has 2 divisors, whose sum is σ = 3210230453114. Its totient is φ = 3210230453112.
The previous prime is 3210230453083. The next prime is 3210230453149. The reversal of 3210230453113 is 3113540320123.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2442728303929 + 767502149184 = 1562923^2 + 876072^2 .
It is a cyclic number.
It is not a de Polignac number, because 3210230453113 - 29 = 3210230452601 is a prime.
It is not a weakly prime, because it can be changed into another prime (3210230453413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1605115226556 + 1605115226557.
It is an arithmetic number, because the mean of its divisors is an integer number (1605115226557).
Almost surely, 23210230453113 is an apocalyptic number.
It is an amenable number.
3210230453113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3210230453113 is an equidigital number, since it uses as much as digits as its factorization.
3210230453113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 3210230453113 its reverse (3113540320123), we get a palindrome (6323770773236).
The spelling of 3210230453113 in words is "three trillion, two hundred ten billion, two hundred thirty million, four hundred fifty-three thousand, one hundred thirteen".
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