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32110123130957 is a prime number
BaseRepresentation
bin1110100110100001110000…
…11110111010000001001101
311012200200211200122021202002
413103100320132322001031
513202043013010142312
6152143104213042045
76522610533146144
oct723207036720115
9135620750567662
1032110123130957
11a25a910442073
1237271a7326325
1314bbc82852571
147d01d151275b
153aa3d0ac24c2
hex1d34387ba04d

32110123130957 has 2 divisors, whose sum is σ = 32110123130958. Its totient is φ = 32110123130956.

The previous prime is 32110123130933. The next prime is 32110123131091. The reversal of 32110123130957 is 75903132101123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29556499954921 + 2553623176036 = 5436589^2 + 1598006^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32110123130957 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 32110123130957.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32110123130927) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16055061565478 + 16055061565479.

It is an arithmetic number, because the mean of its divisors is an integer number (16055061565479).

Almost surely, 232110123130957 is an apocalyptic number.

It is an amenable number.

32110123130957 is a deficient number, since it is larger than the sum of its proper divisors (1).

32110123130957 is an equidigital number, since it uses as much as digits as its factorization.

32110123130957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34020, while the sum is 38.

The spelling of 32110123130957 in words is "thirty-two trillion, one hundred ten billion, one hundred twenty-three million, one hundred thirty thousand, nine hundred fifty-seven".