Base | Representation |
---|---|
bin | 101110101110100100101… |
… | …010010101000110011010 |
3 | 102100222102022001101221221 |
4 | 232232210222111012122 |
5 | 410102314400130020 |
6 | 10455054352122254 |
7 | 450665062153366 |
oct | 56564452250632 |
9 | 12328368041857 |
10 | 3211103130010 |
11 | 1028904004886 |
12 | 43a3bbb3638a |
13 | 1a3a62244a99 |
14 | b15bd8522a6 |
15 | 587dc8296aa |
hex | 2eba4a9519a |
3211103130010 has 8 divisors (see below), whose sum is σ = 5779985634036. Its totient is φ = 1284441252000.
The previous prime is 3211103129959. The next prime is 3211103130049. The reversal of 3211103130010 is 100313011123.
3211103130010 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 3155174190961 + 55928939049 = 1776281^2 + 236493^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×32111031300102 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160555156491 + ... + 160555156510.
Almost surely, 23211103130010 is an apocalyptic number.
3211103130010 is a deficient number, since it is larger than the sum of its proper divisors (2568882504026).
3211103130010 is a wasteful number, since it uses less digits than its factorization.
3211103130010 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 321110313008.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 3211103130010 its reverse (100313011123), we get a palindrome (3311416141133).
The spelling of 3211103130010 in words is "three trillion, two hundred eleven billion, one hundred three million, one hundred thirty thousand, ten".
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