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321113001197 is a prime number
BaseRepresentation
bin1001010110000111101…
…00111000110011101101
31010200211220202121121102
410223003310320303231
520230114412014242
6403303422012445
732125323321602
oct4530364706355
91120756677542
10321113001197
11114201a1061a
1252298117125
1324385c89b21
141178318c6a9
158545ecce32
hex4ac3d38ced

321113001197 has 2 divisors, whose sum is σ = 321113001198. Its totient is φ = 321113001196.

The previous prime is 321113001191. The next prime is 321113001211. The reversal of 321113001197 is 791100311123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 229537768201 + 91575232996 = 479101^2 + 302614^2 .

It is a cyclic number.

It is not a de Polignac number, because 321113001197 - 26 = 321113001133 is a prime.

It is a super-3 number, since 3×3211130011973 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (321113001191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160556500598 + 160556500599.

It is an arithmetic number, because the mean of its divisors is an integer number (160556500599).

Almost surely, 2321113001197 is an apocalyptic number.

It is an amenable number.

321113001197 is a deficient number, since it is larger than the sum of its proper divisors (1).

321113001197 is an equidigital number, since it uses as much as digits as its factorization.

321113001197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1134, while the sum is 29.

The spelling of 321113001197 in words is "three hundred twenty-one billion, one hundred thirteen million, one thousand, one hundred ninety-seven".