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321113020223143 is a prime number
BaseRepresentation
bin100100100000011001111001…
…1100000001100111010100111
31120002222002211111022201122101
41021000303303200030322213
5314042103431134120033
63054541141320312531
7124431435663352531
oct11100636340147247
91502862744281571
10321113020223143
11933532a3575945
1230021a30912747
1310a23a9bac6665
145941d4b46c851
15271cd4728e97d
hex1240cf380cea7

321113020223143 has 2 divisors, whose sum is σ = 321113020223144. Its totient is φ = 321113020223142.

The previous prime is 321113020223123. The next prime is 321113020223159. The reversal of 321113020223143 is 341322020311123.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 321113020223143 - 213 = 321113020214951 is a prime.

It is a super-3 number, since 3×3211130202231433 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (321113020223123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160556510111571 + 160556510111572.

It is an arithmetic number, because the mean of its divisors is an integer number (160556510111572).

Almost surely, 2321113020223143 is an apocalyptic number.

321113020223143 is a deficient number, since it is larger than the sum of its proper divisors (1).

321113020223143 is an equidigital number, since it uses as much as digits as its factorization.

321113020223143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 321113020223143 its reverse (341322020311123), we get a palindrome (662435040534266).

The spelling of 321113020223143 in words is "three hundred twenty-one trillion, one hundred thirteen billion, twenty million, two hundred twenty-three thousand, one hundred forty-three".