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321113219893 is a prime number
BaseRepresentation
bin1001010110000111101…
…01101110001100110101
31010200211221011201121021
410223003311232030311
520230114441014033
6403303430421141
732125325222314
oct4530365561465
91120757151537
10321113219893
1111420204a964
12522982017b1
132438603552b
141178320827b
158546022b2d
hex4ac3d6e335

321113219893 has 2 divisors, whose sum is σ = 321113219894. Its totient is φ = 321113219892.

The previous prime is 321113219837. The next prime is 321113219909. The reversal of 321113219893 is 398912311123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 240180366724 + 80932853169 = 490082^2 + 284487^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-321113219893 is a prime.

It is a super-3 number, since 3×3211132198933 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (321113219813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160556609946 + 160556609947.

It is an arithmetic number, because the mean of its divisors is an integer number (160556609947).

Almost surely, 2321113219893 is an apocalyptic number.

It is an amenable number.

321113219893 is a deficient number, since it is larger than the sum of its proper divisors (1).

321113219893 is an equidigital number, since it uses as much as digits as its factorization.

321113219893 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69984, while the sum is 43.

The spelling of 321113219893 in words is "three hundred twenty-one billion, one hundred thirteen million, two hundred nineteen thousand, eight hundred ninety-three".