32111341124143 has 2 divisors, whose sum is σ = 32111341124144. Its totient is φ = 32111341124142.

The previous prime is 32111341124069. The next prime is 32111341124147. The reversal of 32111341124143 is 34142114311123.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 32111341124143 - 2¹³ = 32111341115951 is a prime.

It is a super-3 number, since 3×32111341124143³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32111341124147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16055670562071 + 16055670562072.

It is an arithmetic number, because the mean of its divisors is an integer number (16055670562072).

Almost surely, 2^{32111341124143} is an apocalyptic number.

32111341124143 is a deficient number, since it is larger than the sum of its proper divisors (1).

32111341124143 is an equidigital number, since it uses as much as digits as its factorization.

32111341124143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 31.

Adding to 32111341124143 its reverse (34142114311123), we get a palindrome (66253455435266).

The spelling of 32111341124143 in words is "thirty-two trillion, one hundred eleven billion, three hundred forty-one million, one hundred twenty-four thousand, one hundred forty-three".