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321131113001 is a prime number
BaseRepresentation
bin1001010110001001110…
…01111110101000101001
31010200220011211210022222
410223010321332220221
520230134031104001
6403305310123425
732125633264646
oct4530471765051
91120804753288
10321131113001
11114211161256
12522a21b0575
132438995b97a
1411785744dcd
1585478a961b
hex4ac4e7ea29

321131113001 has 2 divisors, whose sum is σ = 321131113002. Its totient is φ = 321131113000.

The previous prime is 321131112989. The next prime is 321131113049. The reversal of 321131113001 is 100311131123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 182285448601 + 138845664400 = 426949^2 + 372620^2 .

It is a cyclic number.

It is not a de Polignac number, because 321131113001 - 214 = 321131096617 is a prime.

It is a super-2 number, since 2×3211311130012 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (321131103001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160565556500 + 160565556501.

It is an arithmetic number, because the mean of its divisors is an integer number (160565556501).

Almost surely, 2321131113001 is an apocalyptic number.

It is an amenable number.

321131113001 is a deficient number, since it is larger than the sum of its proper divisors (1).

321131113001 is an equidigital number, since it uses as much as digits as its factorization.

321131113001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 321131113001 its reverse (100311131123), we get a palindrome (421442244124).

The spelling of 321131113001 in words is "three hundred twenty-one billion, one hundred thirty-one million, one hundred thirteen thousand, one".