Base | Representation |
---|---|
bin | 1001010110001001110… |
… | …10011000110000110111 |
3 | 1010200220012001020010202 |
4 | 10223010322120300313 |
5 | 20230134043020043 |
6 | 403305312311115 |
7 | 32125634221655 |
oct | 4530472306067 |
9 | 1120805036122 |
10 | 321131220023 |
11 | 1142112246a9 |
12 | 522a224249b |
13 | 243899985b3 |
14 | 11785771dd5 |
15 | 85478cb1b8 |
hex | 4ac4e98c37 |
321131220023 has 2 divisors, whose sum is σ = 321131220024. Its totient is φ = 321131220022.
The previous prime is 321131220013. The next prime is 321131220041. The reversal of 321131220023 is 320022131123.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 321131220023 - 220 = 321130171447 is a prime.
It is a super-2 number, since 2×3211312200232 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 321131219977 and 321131220004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (321131220013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160565610011 + 160565610012.
It is an arithmetic number, because the mean of its divisors is an integer number (160565610012).
Almost surely, 2321131220023 is an apocalyptic number.
321131220023 is a deficient number, since it is larger than the sum of its proper divisors (1).
321131220023 is an equidigital number, since it uses as much as digits as its factorization.
321131220023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 321131220023 its reverse (320022131123), we get a palindrome (641153351146).
The spelling of 321131220023 in words is "three hundred twenty-one billion, one hundred thirty-one million, two hundred twenty thousand, twenty-three".
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