Base | Representation |
---|---|
bin | 1001010110001001110… |
… | …10110001001100111111 |
3 | 1010200220012020022110022 |
4 | 10223010322301030333 |
5 | 20230134104221002 |
6 | 403305314402355 |
7 | 32125635116552 |
oct | 4530472611477 |
9 | 1120805208408 |
10 | 321131320127 |
11 | 114211292932 |
12 | 522a22903bb |
13 | 24389a02027 |
14 | 1178579a699 |
15 | 85478eaba2 |
hex | 4ac4eb133f |
321131320127 has 2 divisors, whose sum is σ = 321131320128. Its totient is φ = 321131320126.
The previous prime is 321131320049. The next prime is 321131320183. The reversal of 321131320127 is 721023131123.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-321131320127 is a prime.
It is a super-2 number, since 2×3211313201272 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 321131320096 and 321131320105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (321131326127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160565660063 + 160565660064.
It is an arithmetic number, because the mean of its divisors is an integer number (160565660064).
Almost surely, 2321131320127 is an apocalyptic number.
321131320127 is a deficient number, since it is larger than the sum of its proper divisors (1).
321131320127 is an equidigital number, since it uses as much as digits as its factorization.
321131320127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
The spelling of 321131320127 in words is "three hundred twenty-one billion, one hundred thirty-one million, three hundred twenty thousand, one hundred twenty-seven".
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