Base | Representation |
---|---|
bin | 100100100000100010011011… |
… | …1000101110001000100011011 |
3 | 1120010000212002210221122201102 |
4 | 1021001010313011301010123 |
5 | 314042403433001410321 |
6 | 3054553410452342015 |
7 | 124432654552120511 |
oct | 11101046705610433 |
9 | 1503025083848642 |
10 | 321131334013211 |
11 | 933600411a0437 |
12 | 300254a201490b |
13 | 10a2572a042727 |
14 | 5942ba781c4b1 |
15 | 271d569e7cc0b |
hex | 124113717111b |
321131334013211 has 2 divisors, whose sum is σ = 321131334013212. Its totient is φ = 321131334013210.
The previous prime is 321131334013207. The next prime is 321131334013213. The reversal of 321131334013211 is 112310433131123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 321131334013211 - 22 = 321131334013207 is a prime.
Together with 321131334013213, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (321131334013213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160565667006605 + 160565667006606.
It is an arithmetic number, because the mean of its divisors is an integer number (160565667006606).
Almost surely, 2321131334013211 is an apocalyptic number.
321131334013211 is a deficient number, since it is larger than the sum of its proper divisors (1).
321131334013211 is an equidigital number, since it uses as much as digits as its factorization.
321131334013211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 29.
Adding to 321131334013211 its reverse (112310433131123), we get a palindrome (433441767144334).
The spelling of 321131334013211 in words is "three hundred twenty-one trillion, one hundred thirty-one billion, three hundred thirty-four million, thirteen thousand, two hundred eleven".
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