Base | Representation |
---|---|
bin | 1001010110001001110… |
… | …11001010110101110101 |
3 | 1010200220012102122111201 |
4 | 10223010323022311311 |
5 | 20230134121101031 |
6 | 403305320532501 |
7 | 32125636034662 |
oct | 4530473126565 |
9 | 1120805378451 |
10 | 321131425141 |
11 | 11421135481a |
12 | 522a2321131 |
13 | 24389a3aa77 |
14 | 117857c6a69 |
15 | 854791bd61 |
hex | 4ac4ecad75 |
321131425141 has 2 divisors, whose sum is σ = 321131425142. Its totient is φ = 321131425140.
The previous prime is 321131425081. The next prime is 321131425163. The reversal of 321131425141 is 141524131123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 294708922641 + 26422502500 = 542871^2 + 162550^2 .
It is an emirp because it is prime and its reverse (141524131123) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-321131425141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (321131422141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160565712570 + 160565712571.
It is an arithmetic number, because the mean of its divisors is an integer number (160565712571).
Almost surely, 2321131425141 is an apocalyptic number.
It is an amenable number.
321131425141 is a deficient number, since it is larger than the sum of its proper divisors (1).
321131425141 is an equidigital number, since it uses as much as digits as its factorization.
321131425141 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2880, while the sum is 28.
Adding to 321131425141 its reverse (141524131123), we get a palindrome (462655556264).
The spelling of 321131425141 in words is "three hundred twenty-one billion, one hundred thirty-one million, four hundred twenty-five thousand, one hundred forty-one".
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