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321131425141 is a prime number
BaseRepresentation
bin1001010110001001110…
…11001010110101110101
31010200220012102122111201
410223010323022311311
520230134121101031
6403305320532501
732125636034662
oct4530473126565
91120805378451
10321131425141
1111421135481a
12522a2321131
1324389a3aa77
14117857c6a69
15854791bd61
hex4ac4ecad75

321131425141 has 2 divisors, whose sum is σ = 321131425142. Its totient is φ = 321131425140.

The previous prime is 321131425081. The next prime is 321131425163. The reversal of 321131425141 is 141524131123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 294708922641 + 26422502500 = 542871^2 + 162550^2 .

It is an emirp because it is prime and its reverse (141524131123) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-321131425141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (321131422141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160565712570 + 160565712571.

It is an arithmetic number, because the mean of its divisors is an integer number (160565712571).

Almost surely, 2321131425141 is an apocalyptic number.

It is an amenable number.

321131425141 is a deficient number, since it is larger than the sum of its proper divisors (1).

321131425141 is an equidigital number, since it uses as much as digits as its factorization.

321131425141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2880, while the sum is 28.

Adding to 321131425141 its reverse (141524131123), we get a palindrome (462655556264).

The spelling of 321131425141 in words is "three hundred twenty-one billion, one hundred thirty-one million, four hundred twenty-five thousand, one hundred forty-one".