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3211330012097 is a prime number
BaseRepresentation
bin101110101110110010001…
…011110100001111000001
3102101000000002222012200012
4232232302023310033001
5410103300440341342
610455133055034305
7451003515502244
oct56566213641701
912330002865605
103211330012097
111028a10088739
1243a463b0b995
131a3a9a251b3c
14b1601a3125b
15588026e3b82
hex2ebb22f43c1

3211330012097 has 2 divisors, whose sum is σ = 3211330012098. Its totient is φ = 3211330012096.

The previous prime is 3211330012063. The next prime is 3211330012129. The reversal of 3211330012097 is 7902100331123.

It is an a-pointer prime, because the next prime (3211330012129) can be obtained adding 3211330012097 to its sum of digits (32).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3181261064881 + 30068947216 = 1783609^2 + 173404^2 .

It is a cyclic number.

It is not a de Polignac number, because 3211330012097 - 210 = 3211330011073 is a prime.

It is not a weakly prime, because it can be changed into another prime (3211330017097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1605665006048 + 1605665006049.

It is an arithmetic number, because the mean of its divisors is an integer number (1605665006049).

Almost surely, 23211330012097 is an apocalyptic number.

It is an amenable number.

3211330012097 is a deficient number, since it is larger than the sum of its proper divisors (1).

3211330012097 is an equidigital number, since it uses as much as digits as its factorization.

3211330012097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6804, while the sum is 32.

The spelling of 3211330012097 in words is "three trillion, two hundred eleven billion, three hundred thirty million, twelve thousand, ninety-seven".