Base | Representation |
---|---|
bin | 1110100110100111111011… |
… | …10110000011101001010001 |
3 | 11012201000101110012200012012 |
4 | 13103103331312003221101 |
5 | 13202121303140424444 |
6 | 152144412535112305 |
7 | 6523055560545044 |
oct | 723237566035121 |
9 | 135630343180165 |
10 | 32113434311249 |
11 | a26125a522905 |
12 | 3727970212695 |
13 | 14bc38c84a745 |
14 | 7d042719cc5b |
15 | 3aa526632b9e |
hex | 1d34fdd83a51 |
32113434311249 has 2 divisors, whose sum is σ = 32113434311250. Its totient is φ = 32113434311248.
The previous prime is 32113434311213. The next prime is 32113434311327. The reversal of 32113434311249 is 94211343431123.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19903581363649 + 12209852947600 = 4461343^2 + 3494260^2 .
It is a cyclic number.
It is not a de Polignac number, because 32113434311249 - 228 = 32113165875793 is a prime.
It is not a weakly prime, because it can be changed into another prime (32113434341249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16056717155624 + 16056717155625.
It is an arithmetic number, because the mean of its divisors is an integer number (16056717155625).
Almost surely, 232113434311249 is an apocalyptic number.
It is an amenable number.
32113434311249 is a deficient number, since it is larger than the sum of its proper divisors (1).
32113434311249 is an equidigital number, since it uses as much as digits as its factorization.
32113434311249 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 186624, while the sum is 41.
The spelling of 32113434311249 in words is "thirty-two trillion, one hundred thirteen billion, four hundred thirty-four million, three hundred eleven thousand, two hundred forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •