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32113434311213 is a prime number
BaseRepresentation
bin1110100110100111111011…
…10110000011101000101101
311012201000101110012200010212
413103103331312003220231
513202121303140424323
6152144412535112205
76523055560544663
oct723237566035055
9135630343180125
1032113434311213
11a26125a522882
123727970212665
1314bc38c84a718
147d042719cc33
153aa526632b78
hex1d34fdd83a2d

32113434311213 has 2 divisors, whose sum is σ = 32113434311214. Its totient is φ = 32113434311212.

The previous prime is 32113434311171. The next prime is 32113434311249. The reversal of 32113434311213 is 31211343431123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16124296467049 + 15989137844164 = 4015507^2 + 3998642^2 .

It is a cyclic number.

It is not a de Polignac number, because 32113434311213 - 28 = 32113434310957 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 32113434311213.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32113434311713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16056717155606 + 16056717155607.

It is an arithmetic number, because the mean of its divisors is an integer number (16056717155607).

Almost surely, 232113434311213 is an apocalyptic number.

It is an amenable number.

32113434311213 is a deficient number, since it is larger than the sum of its proper divisors (1).

32113434311213 is an equidigital number, since it uses as much as digits as its factorization.

32113434311213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15552, while the sum is 32.

Adding to 32113434311213 its reverse (31211343431123), we get a palindrome (63324777742336).

The spelling of 32113434311213 in words is "thirty-two trillion, one hundred thirteen billion, four hundred thirty-four million, three hundred eleven thousand, two hundred thirteen".