Base | Representation |
---|---|
bin | 1110100110100111111011… |
… | …10110000011101010011011 |
3 | 11012201000101110012200021221 |
4 | 13103103331312003222123 |
5 | 13202121303140430243 |
6 | 152144412535112511 |
7 | 6523055560545211 |
oct | 723237566035233 |
9 | 135630343180257 |
10 | 32113434311323 |
11 | a26125a522972 |
12 | 3727970212737 |
13 | 14bc38c84a7a1 |
14 | 7d042719ccb1 |
15 | 3aa526632bed |
hex | 1d34fdd83a9b |
32113434311323 has 4 divisors (see below), whose sum is σ = 32397623995608. Its totient is φ = 31829244627040.
The previous prime is 32113434311249. The next prime is 32113434311327. The reversal of 32113434311323 is 32311343431123.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32113434311323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32113434311327) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142094841973 + ... + 142094842198.
It is an arithmetic number, because the mean of its divisors is an integer number (8099405998902).
Almost surely, 232113434311323 is an apocalyptic number.
32113434311323 is a deficient number, since it is larger than the sum of its proper divisors (284189684285).
32113434311323 is a wasteful number, since it uses less digits than its factorization.
32113434311323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 284189684284.
The product of its digits is 46656, while the sum is 34.
Adding to 32113434311323 its reverse (32311343431123), we get a palindrome (64424777742446).
The spelling of 32113434311323 in words is "thirty-two trillion, one hundred thirteen billion, four hundred thirty-four million, three hundred eleven thousand, three hundred twenty-three".
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