Base | Representation |
---|---|
bin | 1001010110001011000… |
… | …11111011111100110101 |
3 | 1010200220221112121012021 |
4 | 10223011203323330311 |
5 | 20230144340041203 |
6 | 403310341553141 |
7 | 32126125625110 |
oct | 4530543737465 |
9 | 1120827477167 |
10 | 321142112053 |
11 | 114217393a84 |
12 | 522a5a157b1 |
13 | 2438c010199 |
14 | 11786da9577 |
15 | 854882d5bd |
hex | 4ac58fbf35 |
321142112053 has 16 divisors (see below), whose sum is σ = 369418178304. Its totient is φ = 273467496960.
The previous prime is 321142112047. The next prime is 321142112107. The reversal of 321142112053 is 350211241123.
It is not a de Polignac number, because 321142112053 - 25 = 321142112021 is a prime.
It is a super-2 number, since 2×3211421120532 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (321142112003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2101701 + ... + 2249317.
It is an arithmetic number, because the mean of its divisors is an integer number (23088636144).
Almost surely, 2321142112053 is an apocalyptic number.
It is an amenable number.
321142112053 is a deficient number, since it is larger than the sum of its proper divisors (48276066251).
321142112053 is a wasteful number, since it uses less digits than its factorization.
321142112053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 149652.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 321142112053 its reverse (350211241123), we get a palindrome (671353353176).
The spelling of 321142112053 in words is "three hundred twenty-one billion, one hundred forty-two million, one hundred twelve thousand, fifty-three".
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