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321142540051 is a prime number
BaseRepresentation
bin1001010110001011001…
…01100100011100010011
31010200220222100100022001
410223011211210130103
520230144442240201
6403310355054431
732126132356654
oct4530545443423
91120828310261
10321142540051
111142176565a3
12522a5ba1417
132438c12cc38
141178707b52b
1585488b5301
hex4ac5964713

321142540051 has 2 divisors, whose sum is σ = 321142540052. Its totient is φ = 321142540050.

The previous prime is 321142539989. The next prime is 321142540079. The reversal of 321142540051 is 150045241123.

It is an a-pointer prime, because the next prime (321142540079) can be obtained adding 321142540051 to its sum of digits (28).

It is a strong prime.

It is an emirp because it is prime and its reverse (150045241123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 321142540051 - 213 = 321142531859 is a prime.

It is not a weakly prime, because it can be changed into another prime (321142540351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160571270025 + 160571270026.

It is an arithmetic number, because the mean of its divisors is an integer number (160571270026).

Almost surely, 2321142540051 is an apocalyptic number.

321142540051 is a deficient number, since it is larger than the sum of its proper divisors (1).

321142540051 is an equidigital number, since it uses as much as digits as its factorization.

321142540051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 321142540051 its reverse (150045241123), we get a palindrome (471187781174).

The spelling of 321142540051 in words is "three hundred twenty-one billion, one hundred forty-two million, five hundred forty thousand, fifty-one".